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-3x^2-3x+11=2x
We move all terms to the left:
-3x^2-3x+11-(2x)=0
We add all the numbers together, and all the variables
-3x^2-5x+11=0
a = -3; b = -5; c = +11;
Δ = b2-4ac
Δ = -52-4·(-3)·11
Δ = 157
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{157}}{2*-3}=\frac{5-\sqrt{157}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{157}}{2*-3}=\frac{5+\sqrt{157}}{-6} $
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